Math, asked by tovibhakthan, 11 months ago



1. An isosceles triangle has perimeter 30 cm and each of the equal sides is 12 cm. Find the area of
the triangle.

Answers

Answered by alok18092
7

Step-by-step explanation:

Length of the equal sides = 12cm

Perimeter of the triangle = 30cm

Length of the third side = 30 - (12+12) cm = 6cm

Semi perimeter of the triangle(s) = 30/2 cm = 15cm

Using heron's formula,

Area of the triangle = √s (s-a) (s-b) (s-c)

                                       = √15(15 - 12) (15 - 12) (15 - 6)cm2

                                       = √15 × 3 × 3 × 9 cm2

                                       = 9√15 cm2

Answered by monishamoni9314
2

Step-by-step explanation:

perimetr of triangle =a+b+c=30

a+b=12+12=24

so,c=30-(a+b)= 30-24=6

height =144 -9=√134

ar of triangle=1/2×b×h

1/2×6×√135

=3×√135

=34.85sq.cm. because√135=11.61

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