Question

1. An object 2cm in size is placed 30 cm in front of a
concave mirror of focal length 15cm. At what distance
from the mirror should a screen be placed in order
to obtain a sharp image ? what will be the nature
and the seize of the image formed​

Answer 1

Answer:

ho=2cm,u=-30cm,f=-15cm

from mirror formula

1/f=1/v+1/u

1/v=1/f-1/u

1/v= -1/15+1/30

1/v= -2+1/30

v= -30

now

from magnification

hi/ho= -v/u

hi=30×2/-15

hi=-4cm

Explanation:

so image formed at 30cm apart and size of image is 4 cm and nature is real and inverted