Question

1) an object 2cm tall is placed on the axis of a convex lens of focal length of 5cm at a distance of 10m from the optical centre of the lens find the nature position and size of the image

Answer 1

Answer:

f=

5cm

u=

−10m=

−1000cm

v

1

−

u

1

=

f

1

v

1

−

h

1

2cm

−1000

1

=

5

1

v

1

=

5

1

−

1000

1

=

1000

200−1

=

1000

199

v=

5.02cm

5.02cm

m=

u

v

=

−1000

5.02

=

−0.005

m=

h

1

h

2

=

−0.005

2

h

2

=

−0.005

h

2

0.01cm

Explanation: