Question

1. An object falls from a high building and hits the ground in 10.2 s. What is the distance that it fell? Neglect air resistance.

Answer 1

Explanation:

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Answer 2

Let the distance the object fell be h.

Applying the second equation of motion,

 $\\ h = ut +\frac{1}{2} \times g\times t^{2}$

where h= distance traveled

           u = initial velocity

          g = acceleration due to gravity $\\ = 9.8 \frac{m}{s^{2} }$

          t = time taken  

Given,

u $\\ = 0 m/s$

t $\\ = 10.2 s$

Applying the formula,

 $\\ h = 0 \times 10.2 + \frac{1}{2} \times 9.8 \times 10.2^{2}$

$\\ h = \frac{1}{2} \times 9.8 \times 104.04$

$\\ h = 509.796 m$

The height of the building or the distance traveled by the object is 509.796 m.