Question

1. An object having a velocity 4.0 m/s is accelerated at the rate of 2 m/s² for 5.0 s. Find the distance
travelled during the period of acceleration?
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Answer 1

Answer:

Initial velocity= 4 m/sec

time= 5 sec

Rate of accelaration= 2 m/sec

using the formula:

s = ut + 1/2 at2

s = 4 x 5 + 1/2 x 2 x 25    [ square of 5 is 25]

s = 20+ 25

s =45

# distance travelled by the object during the period of accelaration is 45 m