Question

1. An object is dropped from the top of a tower. How much time it will take on falling down to 4.9 m distance? (a)​

Answer 1

Answer:

you can solve this by using 2nd equation of motion

Explanation:

s=vit + 1/2at^2

here intial velocity is zero..

and acceleration is g 9.8m/sec2

4.9=0+1/2(9.8)t2

4.9=9.8÷2t2

1.02=t*2

taking square root

1.01....sec....answer