Question

1. An object is pivoted at a given point. A force of 6.0 N
applied at a normal distance of 25 cm from the pivoted point
rotates the given object. What is the torque of the force?​

Answer 1

Answer:

ur question is incomplete

Answer 2

Answer:

I know the whole question but please never do such types of error again....

MOF=force×perpendicular distance

MOF=6×0.25

I converted 25 cm into m

MOF=1.50 Nm

Hope you will like it and please mark me as brainliest