Question

1. An object is projected with an initial velocity v0 making an angle Θ with the horizontal.

(a) What is the shape of the path of the projectile ?

(b) Obtain an equation for time of flight and horizontal range of the projectile.​

Answer 1

a)projectile motion, an object moves in parabolic path; the path the object follows is called its trajectory.

b)The duration of the flight before the object hits the ground is given as T = \sqrt{\frac{2H}{g}}. In the horizontal direction, the object travels at a constant speed v0 during the flight. The range R (in the horizontal direction) is given as: R=v0⋅T=v0√2Hg R = v 0 ⋅ T = v 0 2 H g

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Answer 2

Answer:

a.) projectile motion an object moves in a parabolic path , the path the object follow is called trajectory.