Question

1. An object is thrown straight up with a speed of 30 m/s. How high above the point of release is it and what is its velocity after (1) 23 (2) 6 s? How high does it rise? 9.8 m/s2 (10.4 m/s; 40.4 m; - 28.8 m/s 3.6 m; 45.9 m)​

Answer 1

Answer:

10.4m/s

40.4m

Explanation:

v-u=at

v1-u=-g(2)

v1-30=-(9..8)^2

v1=30-19.6

 =10.4m/s

h1=ut+1/2at

  =30*2+1/2(-g)2^2

   =60-(-9.8\2)*4^2

   =60-19.6

   =40.4m

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