Physics, asked by aryamann7, 4 hours ago

1. An object moves along a square boundary of side 30 m such that it completes 1 round in 20 second. Find distance, displacement, speed & velocity after time 1min 30sec.​

Answers

Answered by dipsikhapanja
0

Answer:

Explanation:

In time 20 secs the object moves 30 m

in time 1 secs the object moves 30/20 m

in time 90 secs(1 min 30 secs) the object moves 30/20 *90m

=30*4.5m

= 135m------ and of distance

therefore speed is distance/time= 135/90 m/s = 1.5 m/s

total perimeter = 30* 4m

=120m

the object covered 135m

displacement is the shortest distance covered

therefore the displacement is 135-120 m = 15 m

velocity = displacement /time = 15/90 m/s =0.16m/s

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