1) An object of mass 40 kg is raised to a height of 5m above the ground what is its potential energy if the object is allowed to fall find its kinetic energy when it is half way down.
Answers
Answered by
0
Answer:
Potential energy = mgh
= 40×10×5
= 2000joule
at heightest point h = 5m , velocity u = 0
half way down = 2.5m
from 3rd equation of NLM,
v² = u²+2as
v² = 0 +2×10×2.5
v² = 50m/sec
Explanation:
so, kinetic energy on its half way = (1/2)mv²
= (1/2)×40×50
= 1000joule answer
Answered by
2
Answer:
Answer in attachment.
Hope it will help you .
Attachments:
Similar questions