Question

1. An object thrown vertically upwards
reaches a height of 500 m. What was
its initial velocity? How long will the
object take to come back to the
earth? Assume g = 10 m/s2​

Answer 1

Answer:

Using a formula for projectile motion of Time of flight is

$t = \sqrt{2h \div g}$

In the vertical direction take a=g

According to formula.

$t = \sqrt{2 \times 500 \div 10}$

$= \sqrt{1000 \div 10}$

$= \sqrt{100}$

$t = 10s$

Therefore object will take 10s to come back to the Earth.

Answer 2

Answer:

This is your answer.

Hope it will help you..