Question

1) An objects is placed at 50 cm from a concave mirror of radius of curvature 60 cm. find the image
distance. what is the nature of the image.​

Answer 1

Answer:

here is your answer

hope this will help u

Answer 2

$\huge \bigstar$$\huge\bold{\mathtt{\purple{A{\pink{N{\green{S{\blue{W{\red{E{\orange{R}}}}}}}}}}}}}$$\huge \Rightarrow$

$\Large \bold \red{Solution}\Rightarrow$

$\bold {Given\: data}\longrightarrow$

Concave mirror, u = -50 cm, R = -60 cm, $\large \upsilon$ = ?

$\int = \frac {R}{2}= - \frac {60}{2}=-30cm$

$\frac{1}{\upsilon} + \frac{1}{u} = \frac{1}{\int} </p><p>\\ \\ \Rightarrow = \frac{1}{\upsilon} = \frac{1}{\int} - \frac{1}{u} = \frac{1}{-30 cm} - \frac{1}{-50cm} \\ \\ = - ( \frac{1}{30cm} - \frac{1}{50cm}) \\ \\ = -( \frac{5-3}{150cm} )= - \frac{2}{150cm} = - \frac{1}{75cm} \\ \\ \therefore \upsilon = - 75cm$

This give the image distance.

The image is real,inverted and magnified.It is formed in front of the mirror.