Question

1. An observer 1.6 m tall is 30.5 away from the
tower. The angle of the elevation
the elevation of the top a
the tower from her eyes is
45° . What is
the freight g the tower.​

Answer 1

Answer:

Draw BE ⊥ CD

Then CE = AB = 1.6m

BE = AC = 30.5m

DE/BE=tan45∘=1

⇒DE=BE=30.5

∴ CD = CE + DE = (1.6 + 30.5) m = 32.1m

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