1 and -1 are the zeroes of the polynomial ax cube +x square-2x+b, find the values of and b
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zeros = -1 and 1
polynomial P(x) = ax^3 +x^2-2x+b
P(-1) = a(-1)^3 + (-1)^2 -2 (-1) +b
- a +1+2+b = 0
b-a= -3
or, a-b=3
P(1) = ax1^3 + 1^2 -2x1 +b
a+b = 1
equating values a = 2 and b = -1
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