Question

(1) Answers the question

Find the width and area of the rectangular field whose lenght is 240m and perimeter is 680m.​

Answer 1

Answer:

this is answer i hope it helps you

Answer 2

Correct Question:-

Find the width (breadth) and area of rectangular field whose length is 240 cm and perimeter is 680 cm.

Given:-

• Length of rectangle = 240 cm
• Perimeter of rectangle = 680 cm

To Find:-

• Breadth and area of rectangle

Solution:-

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \mathfrak{ \underline{ \purple{Formula \: to \: calculate \: the \: perimeter \: of \: rectangle}}}$

$\boxed{ \green{ \mathfrak{ \large{ \star \: \: \: \: \: \: { \red{perimeter = 2(length + breadth)}}}}}}$

As per question,

$\large{ \tt \longmapsto \: \: \: \: \: \: \: \: \: \: 2(240 + {\mathfrak{ \blue{breadth}}}) = 680}$

$\large{ \tt \longmapsto \: \: \: \: \: \: \: \: \: \: 240 + \mathfrak{ \blue{breadth}}= \frac{680}{2}}$

$\large{ \tt \longmapsto \: \: \: \: \: \: \: \: \: \mathfrak{ \blue{breadth}} = 340 - 240}$

$\large{ \tt \longmapsto \: \: \: \: \: \: \: \: \: \mathfrak{ \blue{ breadth}} = \boxed{ \rm{100 \: cm}}} \star$

Now, we have to find out the area of rectangle.

$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \mathfrak{ \underline{ \purple{Formula \: to \: calculate \: the \: area \: of \: rectangle}}}$

$\boxed{ \green{ \mathfrak{ \large{ \star \: \: \: \: \: \: { \red{area = length \times breadth}}}}}}$

According to question,

$\large{ \tt \longmapsto \: \: \: \: \: \: \: \: \: \: {\mathfrak{ \blue{area}}}=240 \times 100}$

$\large{ \tt \longmapsto \: \: \: \: \: \: \: \: \: \: \mathfrak{ \blue{area}} = \boxed{ \rm{24000 \: {cm}^{2} }}} \star$

Hence:

• The area and breadth of rectangle are 24000 cm² and 100 cm.