Question

1. ara.
Length of rectangle is 10 cm more than twice of breadth. Perimeter is 540 cm. Find Length and breadth and also find area.​

Answer 1

Answer:

Step-by-step explanation:perimeter of the rectangle =2(l+b)30=2(10+b)30/2=10+b15=10+b15-10=b5cm=b10cm=l

Answer 2

Given:

• Length of rectangle is 10 cm more than twice of breadth.
• Perimeter of Rectangle = 540 cm

⠀⠀⠀

To find:

• Length & breadth of rectangle
• Area of rectangle

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀

☯ Let's consider breadth of rectangle be x cm.

Then, Length of rectangle will be (2x + 10) cm

⠀⠀⠀

$\underline{\bigstar\:\boldsymbol{According\:to\:the\:question\::}}$

• Perimeter of Rectangle = 540 cm

⠀⠀⠀

$\bf{\dag}\;{\underline{\frak{As\;we\;know\;that,}}}$

$\star\;{\boxed{\sf{\pink{Perimeter_{\;(rectangle)} = 2(length + breadth)}}}}$

$:\implies\sf 2[(2x + 10) + x] = 540$

$:\implies\sf (2x + 10) + x = \cancel{ \dfrac{540}{2}}$

$:\implies\sf 3x + 10 = 270$

$:\implies\sf 3x = 270 - 10$

$:\implies\sf 3x = 260$

$:\implies\sf x = \cancel{ \dfrac{260}{3}}$

$:\implies{\underline{\boxed{\frak{\purple{x = 86.7}}}}}\;\bigstar$

Therefore,

⠀⠀⠀

• Breadth of rectangle, x = 86.7 cm
• Length of rectangle, (2x + 10) = 2 × 86.7 + 10 = 173.4 + 10 = 183.4 cm

⠀⠀⠀⠀━━━━━━━━━━━━━━━━━━━━━⠀⠀⠀⠀⠀

$\bf{\dag}\;{\underline{\frak{Now,\:Finding\:area\:of\:rectangle,}}}$

$\star\;{\boxed{\sf{\pink{Area_{\;(rectangle)} = length \times breadth}}}}$

$:\implies\sf Area_{\;(rectangle)} = 183.4 \times 86.7$

$:\implies{\underline{\boxed{\frak{\purple{Area_{\;(rectangle)} = 15900.78\:cm^2}}}}}\;\bigstar$

$\therefore\:{\underline{\sf{Area\:of\:rectangle\:is\; \bf{15900.78\:cm^2}.}}}$