Question

1)Arace track is in form of a ring whose inner circumference is 528 m and the outer circumference is 616 m
Find the width of the track​

Answer 1

Solution:

Outer circumference = 616 m

Radius R $\frac{C}{2\pi}=\frac{616\times7}{2\times22}=98\ m$

=98 m

Inner circumference = 528 m

Inner radius=$\frac{528\times7}{2\times22}=84\ m$

=84 m

Width of track = R - r

= 98 - 84 = 14 m

Answer 2

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