Question

1. Area of rectangle whose sides are 5y and 7y can be given as- *

1 point

5y²

7y²

12y²

35y²

​

Answer 1

★GIVEN★

• Length = 5y
• Breadth = 7y

★To Find★

The area of the rectangle.

★SOLUTION★

Area of rectangle = Length × Breadth

=> Area = 5y × 7y

=> Area = 35y²

Therefore,

The area of the rectangle is 35y².

So, your answer is option (d) 35y².

Answer 2

$\huge {{\red{\fbox{Answer:}}}}$

$\large \bold{Given:}$

$\sf\rightarrow{Length \: of \: rectangle = 7y}$

$\sf\rightarrow{Breadth\: of \: rectangle = 5y}$

$\large \bold{To \: find:}$

$\leadsto \sf{Area \: of \: rectangle}$

$\large \bold{Formula \: required:}$

$\sf \longmapsto{Area \: of \: rectangle = l \times b}$

$\large \bold{According \: to \: question:}$

$\sf\implies{∵Area \: of \: rectangle = l \times b}$

$\sf\implies{∴Area \: of \: rectangle = 7y \times 5y}$

$\sf \implies{∴Area \: of \: rectangle = 35 {y}^{2} }$

$\large\bold{Explore \: more:}$

$\sf\longmapsto{Perimeter \: of \: rectangle = 2(l + b)}$

$\sf \longmapsto{Diagonal \: of \: square = \sqrt{ {l}^{2} + {b}^{2} } }$

$\large \bold{Note:}$

$\sf{→Here \: we \: use \: l \: and \: b \: to \: symbolized}$

$\sf{length \: and \: breadth.}$

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