Math, asked by rekhakambli1195, 5 months ago

1.Arjun is twice as old as Shriya . Five years ago his age was three times Shriya age. Find their present age?

Answers

Answered by khizrahasnain
0

Answer:

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Step-by-step explanation:

Let Shriya′s present age is x years. Then, Arjun′s present age will be 2x years. Shriya′s present age is 10 years.

Answered by nupurgupta1152
0

Answer:

Shriya's present age:- 10 years

Arjun's present age:- 20 years

Step-by-step explanation:

Let shriya's present age to be x then Arjun's present age will be 2x

Five years before,

Shriya's age was (x-5) and,

Arjun's age was (2x-5)

ATQ,

  • (2x-5) = 3(x-5)
  • 2x-5 = 3x-15
  • 3x-2x = 15-5
  • x = 10

=> Shriya's present age = 10 years

Now, as we know, Arjun's present age = 2x

  • 2x = 2×10 [ x = 10]
  • 2x = 20

=> Arjun's present age = 20 years

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