Question

1. Arjun takes a loan of ₹1,800 at 14% per annum as a rate of interest. Find the simple
interest and amount he has to pay at the end of 3 years.​

Answer 1

Answer:

• Simple interest is 756 rupees.
• Amount paid at the end of 3 years is 2556 rupees.

Step-by-step explanation:

Given:

• Principal = 1800 rupees
• Rate of interest = 14%
• Time = 3 years

To Find:

• Simple Interest = ?
• Amount = ?

Solution:

According to the question, principal is given,rate of interest is also given,time is also given and we are said to find simple interest and amount.

we have,

• Principal = 1800 rupees
• Rate of interest = 14%
• Time = 3years

As we know that,

.Simple Interest = P × R ×T/100

where,

• p is principal
• r is rate of interest
• t is time

Now putting on forumla

. Simple Interest = 1800×14×3/100

.Simple Interest = 756 rupees

______________________

we have,

• Simple Interest = 756 rupees
• Principal = 1800 rupees

As we know that,

.Amount = Principal + Simple Interest

.Amount = 1800 + 756

.Amount = 2556 rupees

__________________________

Answer 2

➤ Given :-

Principle :- ₹1800

Rate of interest :- 14%

Time :- 3 years

$\:$

➤ To Find :-

The simple interest and total amount to be paid.

$\:$

★ How to do :-

Here, we are given with the principle amount, the rate of interest and the time taken to give back money. We are asked to find the simple interest and the total amount paid back by Arjun at end of the time period. So, first we should find the simple interest by multiplying the principle, rate and time and then divide by 100. The obtained answer will be the simple interest. Later, we can find the total amount by adding the simple interest and the principle. So, let's solve!!

$\:$

➤ Solution :-

Simple Interest :-

${\tt \leadsto \underline{\boxed{\tt \dfrac{P \times R \times T}{100}}}}$

Substitute the given values.

${\tt \leadsto \dfrac{1800 \times 14 \times 3}{100}}$

Cancel the zeros in numerator and denominator

${\tt \leadsto \dfrac{18 \cancel{00} \times 14 \times 3}{1 \cancel{00}} = \dfrac{18 \times 14 \times 3}{1}}$

Multiply the remaining numbers now.

${\tt \leadsto 18 \times 42 = \pink{\underline{\boxed{\tt Rs \: \: 756}}}}$

$\:$

Now, find the total amount.

Total Amount :-

${\tt \leadsto \underline{\boxed{\tt Simple \: Interest + Principle}}}$

Substitute the given values.

${\tt \leadsto 756 + 1800}$

Add the values to get the answer.

${\tt \leadsto \pink{\underline{\boxed{\tt Rs \: \: 2556}}}}$

$\Huge\therefore$ The simple interest is ₹756 and the total amount is ₹2556.

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$\dashrightarrow$ Some related formulas :-

$\small\boxed{\begin{array}{cc}\large\sf\dag \: {\underline{More \: Formulae}} \\ \\ \bigstar \: \sf{Principle :- \dfrac{SI \times 100}{R \times T}} \\ \\\bigstar \: \sf{Rate \: of \: Interest :- \dfrac{SI \times 100}{P \times T}} \\ \\ \bigstar \: \sf{Time :- \dfrac{SI \times 100}{P \times R}}\end{array}}$