Question

1 .At 25°C and 760 mm of Hg pressure a
gas occupies 600 mL volume. What will
be its pressure at a height where
temperature is 10°C and volume of the
gas is 640 mL.​

Answer 1

Answer:-

$p_1 = 76$

$v_1 = 600$

$t_1 = 25 + 273$

$v_1 = 640$

$t_1 = 10 + 273 = 283$

according to combined gas law

$\frac{p_1v_1}{t_1} = \frac{p_2v_1}{t_1}$

$= \frac{(760) \times (600) \times (283)}{(640)(298)}$

$= 676.6 \: mm \: hg$

Answer 2

Answer:

$\huge\bold\red{ANSWER}$

>>>> P1 = 760 mm Hg

V1 = 600 Ml

T1 = 298 K

V2 = 640 Ml

T2 = 283 K

Using

P1V1= P2V2

We get

P2 = 676.6 mm Hg