Question

1. At a certain time, a tree 6 m high yields a
shadow of length 8 m. At the same time a
pole casts a shadow of length 20 m. Find
the length of the pole.
(a) 50 m (b) 15 m (c) 20 m (d) 25 m​

Answer 1

Answer:

let pole height=h

6:8=h:20

6/8=h/20

8h=120

h=120/8

h=15 meter

Answer 2

Given :-

• Height of the tree = 6 m

• Length of the shadow = 8 m

• Pole casts a shadow of length = 20 m

To Find :-

• The length of the pole.

Solution :-

Let the length of the pole be x.

Then,

$:\implies\sf{6:8 = x:20}$

$:\implies\sf{\dfrac{6}{8} = \dfrac{x}{20} }$

$:\implies\sf{8x = 20\times 6 }$

$:\implies\sf{8x = 120 }$

$:\implies\sf{x = \dfrac{120}{8} }$

$:\implies\sf{x = 15\:m}$

Hence, Required length of the pole is 15 m.