Question

1. At what height above the earth’s surface would the value of acceleration due to gravity

be half of what it is on the surface? Take radius of earth to be R.​

Answer 1

Answer:

Height h = (√2-1) R = 0.414 R

( Where R is the radius of earth)

Explanation:

Refer attachment.

Hope it helps!!

Answer 2

Answer:

According to the law of gravitation :

F=GmM r^2

Where F - force exerted on bodies, G- gravitaional constant, m- mass of the body, M- mass of the Earth, r- distance between the body and core of the Earth.

Acceleration due to gravity :

g= F/m= GM/r^2

At surface of the Earth :

r=R and GM/=(R+h) ^2

2R^2=(R+h) ^2

H=(√2-1) R

R=6371 km

H=2637 km

Thus, at a height of approximately 2637 km the Acceleration due to gravity will be half of the Acceleration due to gravity on the surface!

I Hope it will help u.

May u have a wonderful day.