Question

1. At what temperature 28 g of N2 will occupy a volume
of 20 litres at 2 atm?
(a) 300.0 K
(b) 487.2 K
(c) 289.6 K
(d) 283.8 K​

Answer 1

Answer:

(b) 486.2k

Explanation:

PV=nRT or T=  

nR

PV

​  

(n=  

M

m

​  

)

Here, mass of nitrogen m=28g

Volume of nitrogen V=20litres

Pressure P=2atm

∴T=  

28×0.0821

2×20×28

​  

=487.2 K.