Question

1 atom of an element weighs 1.792 × 10⁻²² g. The atomic mass of the element is _______.
(A) 1.192
(B) 17.92
(C) 64
(D) 108

Answer 1

b.1.792..............

Answer 2

Answer:

(D) 108

Explanation:

As per the given data of the question,

We have,

Weight of 1 atom of an element $= 1.792\times10^{-22}g$

Let the atomic mass of the element be = m

As we know that,

Avogadro number of atoms $= 6 \times 10^{23} atoms$

∴ $1mole=6.022 \times 10^{23} atoms$ 

Weight of one mole of atoms = atomic weight  

Weight of one atom $= \frac{m}{6\times 10^{23}} = 1.792\times 10^{-22}$

Thus,

The atomic weight :

$m = 6 \times 10^{23} \times 1.8 \times10^{-22}= 107.9 =108$

Hence, the atomic mass of the element is 108 g/mole.

∴ The correct option is (D).