Question

1. B Calculate the ph of
of 0.25M HCl​

Answer 1

Answer:

HCl is a strong acid that will be full ionized in solution.

HCl → H+ + Cl-

So, the concentration of [H+] = 0.25 M (or 0.25 mol/L).

The equation that relates pH and [H+] is

pH = -log[H+]

so the pH of the 0.25 M HCl solution will be

pH = -log (0.25) = 0.6

hope it's helpful for you