Question

(1 (B) Solving linear equation using rule of transposition
(1) 3 (5x - 2) - 4 (x + 4) = 7 (x - 1) +1​

Answer 1

$\rm{3 (5x - 2) - 4 (x + 4) = 7 (x - 1) +1 \to 15x - 6 - 4x - 16 = 7x - 7 + 1}$

$\longrightarrow\rm{3 (5x - 2) - 4 (x + 4) = 7 (x - 1) +1 \to 15x- 4x - 6- 16 = 7x - 6}$

$\longrightarrow\rm{3 (5x - 2) - 4 (x + 4) = 7 (x - 1) +1 \to 11x - 6- 16 = 7x - 6}$

$\longrightarrow\rm{3 (5x - 2) - 4 (x + 4) = 7 (x - 1) +1 \to 11x - 22 = 7x - 6}$

$\longrightarrow\rm{3 (5x - 2) - 4 (x + 4) = 7 (x - 1) +1 \to 11x-22+22=7x-6+22}$

$\longrightarrow\rm{3 (5x - 2) - 4 (x + 4) = 7 (x - 1) +1 \to 11x=7x+16}$

$\longrightarrow\rm{3 (5x - 2) - 4 (x + 4) = 7 (x - 1) +1 \to 11x-7x=7x+16-7x}$

$\longrightarrow\rm{3 (5x - 2) - 4 (x + 4) = 7 (x - 1) +1 \to 4x = 16 \to x = 16/4 = 4}$

Answer 2

Heya! The value of x = 4