Math, asked by nargisansarialeem, 9 months ago

___ 1. बिंदु P (6, - 8) की मूल बिंदु से दूरी है
(a) 8 मात्रक
(b) 217 मात्रक
(c) 10 मात्रक
(d) 6 मात्रक
The distance of the point P (6,- 8) from the origin is
(a) 8 units
(b) 2V7 units (c) 10 units (d) 6 units
दो संख्याओं का महत्तम समापवर्तक (HCF) 18 और उनका लघुत्तम समापवर्त्य (LCM) 630 है। यदि एक सख्या 508,
दूसरी संख्या है
2.
The HCF oftwo numbers is 18 and their LCM is 630. If one of the numbers is 36, then the other number is
(a) 18
(b) 315
(c) 36
(d) 630
3.
आकृति में, यदि एक वृत्त के परिगत त्रिभुज ABC है, तो AB की लम्बाई है
(a) 12 सेमी (b) 13 सेमी (c) 14 सेमी (d) 15 सेमी
IfAABC is circumscribing a circle in the figure, the length of AB is
(a) 12 cm
(b) 13 cm (c) 14 cm (d) 15 cm​

Answers

Answered by abhi178
1

answer : (1) 10 unit (2) 315

1. distance of the point P(6, -8) from origin (0,0) = √{(6 - 0)² + (-8 - 0)²}

= √{36 + 64} = 10 unit

hence, option (c) is correct choice.

2. HCF of two numbers = 18

LCM of the two numbers = 630

one number is 36

using application,

HCF × LCM = product of two numbers

⇒18 × 630 = 36 × 2nd number

⇒315 = 2nd number.

hence option (b) is correct choice.

3. you didn't added figure. but I think you question is based on concept of tangent.

if two tangents are drawn from a fixed point to the circle. length of both tangent must be same.

apply it and get the answer.

Answered by Anonymous
2

\huge\bold\purple{Answer:-}

1. distance of the point P(6, -8) from origin (0,0) = √{(6 - 0)² + (-8 - 0)²}

= √{36 + 64} = 10 unit

hence, option (c) is correct choice.

2. HCF of two numbers = 18

LCM of the two numbers = 630

one number is 36

using application,

HCF × LCM = product of two numbers

⇒18 × 630 = 36 × 2nd number

⇒315 = 2nd number.

hence option (b) is correct choice.

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