1. Balance following reaction by ion-electron method
Cr20-+ 1 + H+ 12 + Cr3+
Answers
Answered by
2
Answer:
The oxidation half reaction is SO
2
(g)+2H
2
O(l)→SO
4
2−
+4H
+
(aq)+2e
−
.
The reduction half reaction is Cr
2
O
7
2−
(aq)+14H
+
(aq)+6e
−
→2Cr
3+
(aq)+7H
2
O(l).
The oxidation half reaction is multiplied by 3 and added to the reduction half reaction to obtain the balanced redox reaction.
Cr
2
O
7
2−
+3SO
2
(g)+2H
+
(aq)→2Cr
3+
(aq)+3SO
4
2−
(aq)+H
2
O(l)
Answered by
0
Explanation:
The oxidation half reaction is SO
2
(g)+2H
2
O(l)→SO
4
2−
+4H
+
(aq)+2e
−
.
The reduction half reaction is Cr
2
O
7
2−
(aq)+14H
+
(aq)+6e
−
→2Cr
3+
(aq)+7H
2
O(l).
The oxidation half reaction is multiplied by 3 and added to the reduction half reaction to obtain the balanced redox reaction.
Cr
2
O
7
2−
+3SO
2
(g)+2H
+
(aq)→2Cr
3+
(aq)+3SO
4
2−
(aq)+H
2
O(l)
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