Question

1. Balance given reaction in basic medium by oxidation number method.

PbO2 + ClO–

PbO + ClO3​

Answer 1

Answer:

step1: Pb(OH)42- + ClO- → PbO2 + Cl- + OH-

step2:Pb+2(O-2H+1)42- + Cl+1O-2- → Pb+4O-22 + Cl-1- + O-2H+1-

step3:O:Pb+2(O-2H+1)42- → Pb+4O-22 + 2e-

step4:Pb+2(O-2H+1)42- → Pb+4O-22 + 2e-

step5:Pb+2(O-2H+1)42- → Pb+4O-22 + 2e- + 2H2O

step6:

Pb(OH)42- + ClO- → PbO2 + Cl- + 2OH- + H2O