Question

1. Balance the following chemical equations (Use Hit and Trial method)
1.BaCl2 + Na2SO4 --BaSO4 + NaCl
2.KCIO3 -KCI + O2
3.CHA + O2- CO2 + H2O
4. N2 + H2 - NH3
5.Al2O3 + HCI - AICl3 + H2O
6.Cu +AgNO3 - Cu (NO3)2 +Ag
7.Pb (NO3)2 PbO + NO2 + O2
8.FeSO4 - Fe2O3 + SO2 +SO3
9.CaCO3 + HCI-CaCl2 + CO2 + H2O
10.BaCl2 +Al2(SO4)3 --- BaSO4 +AICI:
11.H2S + O2-SO2 + H2O
12.Ag2S + H2O2- Ag2SO4 + H2O​

Answer 1

Answer:

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Explanation:

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Answer 2

1. $Na_2SO_{4} + BaCl_2 => BaSO_4 + Na_2Cl_2$

2. $2KClO_3 => 2KCI + 3O_2$

3. $CH_4 + 2O_2 => CO_2 + 2H_2O$

4.  $N_2 + 3H_2 => 2NH_3$

5. $Al_2O_3 + 6HCI => 2AICl_3 + 3H_2O$

6. $Cu + 2AgNO_3 = > Cu (NO_3)_2 + 2Ag$

7. $2Pb (NO_3)_2 => 2PbO + 2NO_2 + 4O_2$

8.  $2FeSO_4 => Fe_2O_3 + SO_2 +SO_3$

9. $CaCO_3 + 2HCI => CaCl_2 + CO_2 + H_2O$

10. $3BaCl_2 + Al_2(SO_4)_3 => 3BaSO_4 + 2AICI_3$

11. $2H_2S + 3O_2 => 2SO_2 + 2H_2O$

12. $Ag_2S + 4H_2O_2 => Ag_2SO_4 + 4H_2O$