Question

1. Balance the following equations. a) Cz Hg + O2 -> CO2 + H2O b) Fe + Fe2O3 c) Pb (NO3)2 PbO + Noz + O2 d) KCIO3 KCl + O2



who answer correct I will give as brilliant​

Answer 1

Answer:

Answer

KClO

3

→KCl+3O

2

There are 6 O on the right and 3 on the left

so multiply the KClO

3

by 2

2KClO

3

→KCl+3O

2

now there are 6 O on both sides

Balance the K and Cl by multiplying KCl on the right by 2

2KClO

3

→2KCl+3O

2

Answer 2

Answer:

$2y. |1572 {?}^{?} \times \frac{?}{?} |$

$12 {5)7 {2}^{2} }^{?}$

$6. {60 - > 0 - { > }^{2} }^{?}$