1. Balance the reaction Al+O2 -> Al2OA) 4Al+3O2 = 2Al2O3
B) Al+4O2 = 3Al2O4
C) 4Al+3O4 = 2Al2O2
D) 4Al+4O3 = 4Al2O4
Answers
Answered by
2
aloha user ️✋
here is the answer:
4Al + 3O2 --> 2Al2O3
option (a) is correct.
but how?
we have this equation:
◆ Al + O2 -- > Al2O3
we will multiply O2 on LHS by 3 so as to get 6 molecules of oxygen.
also we are going to multiply Al2O3 by 2 so as to get 6 molecules of oxygen.
we see that while multiplying Al2O3 by 2 we get 2Al2 which is 4 molecules of oxygen.
in order to satisfy law of conservation of mass we will multiply Al on LHS by 4.
hence the equation is balanced.
thanks !!
good life !!
here is the answer:
4Al + 3O2 --> 2Al2O3
option (a) is correct.
but how?
we have this equation:
◆ Al + O2 -- > Al2O3
we will multiply O2 on LHS by 3 so as to get 6 molecules of oxygen.
also we are going to multiply Al2O3 by 2 so as to get 6 molecules of oxygen.
we see that while multiplying Al2O3 by 2 we get 2Al2 which is 4 molecules of oxygen.
in order to satisfy law of conservation of mass we will multiply Al on LHS by 4.
hence the equation is balanced.
thanks !!
good life !!
Answered by
2
heya________________________
ur answer goes like this
Al+O2-->Al2O
oxygen is not balanced so add 2 coefficient on RHS
Al+O2-->2Al2O
again aluminium Nd oxygen on LHS r not balanced
4Al+3O2->2Al203
this is ur answer u can Check it as follows
LHS:- Al:-4. RHS :-Al:-4
LHS:-0:-6 RHS:-O:-6.
hope it helps u:-)
ur answer goes like this
Al+O2-->Al2O
oxygen is not balanced so add 2 coefficient on RHS
Al+O2-->2Al2O
again aluminium Nd oxygen on LHS r not balanced
4Al+3O2->2Al203
this is ur answer u can Check it as follows
LHS:- Al:-4. RHS :-Al:-4
LHS:-0:-6 RHS:-O:-6.
hope it helps u:-)
Similar questions