Question

1. Base of a triangle is 11 and height is 7. Base
of another triangle is 13 and height is 5. Find
the ratio of areas of these triangles.​

Answer 1

Step-by-step explanation:

=

Area(△PQR)

Area(△ABC)

=

2

1

×PM×QR

2

1

×AC×BC

=

2

1

×6×10

2

1

×5×9

=

4

3

Hence, Ratio of Area of △ABC:Area of △PQR=3:4

This is only an example u do it by yourself

Answer 2

Answer:

Let,

The triangle having 9 units as base and 5 units as height is ∆ ABC

And,the triangle having 10 units as base and 6 units as height is ∆ PQR

___________________

Now,

Area of ∆ ABC = (base × height)/2

Area of ∆ ABC =(9×5)/2

Area of ∆ ABC = 45/2 = 22.5 unit²  

-----------------------

Area of ∆ PQR = (10×6)/2

Area of ∆ PQR = 10×3=30 unit²

--------------------

Ratio = 22.5 : 30

Ratio= 225:300

Ratio = 3:4

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