1. Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 6. Find the ratio of areas of these triangles.
Answers
Answered by
8
Answer:
3:4
Step-by-step explanation:
For 1st triangle,
Area=1/2×base×height
=(1/2×9×5)cm^2
=22.5 cm^2
=225/10cm^2
For 2nd triangle,
Area=1/2×base×height
=(1/2×10×6)cm^2
=30cm^2
So,
Ratio of areas of the two triangles is
=(225/10)/30
=225/10×1/30
=15/20
=3/4
=3:4
HOPE THIS ANSWER HELPS YOU....
Answered by
7
Answer:
Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.
Given:
BC = 9, AB = 5, PQ = 6 and QR = 10.
∴A(△ABC)/A(△PQR)
=AB×BC/PQ×QR
=5×9/6×10
=3/4
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