Math, asked by atharva014, 11 months ago



1. Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 6. Find the ratio of areas of these triangles.​

Answers

Answered by ShibajiPal
8

Answer:

3:4

Step-by-step explanation:

For 1st triangle,

Area=1/2×base×height

=(1/2×9×5)cm^2

=22.5 cm^2

=225/10cm^2

For 2nd triangle,

Area=1/2×base×height

=(1/2×10×6)cm^2

=30cm^2

So,

Ratio of areas of the two triangles is

=(225/10)/30

=225/10×1/30

=15/20

=3/4

=3:4

HOPE THIS ANSWER HELPS YOU....

Answered by BlackWizard
7

Answer:

Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.

Given:

BC = 9, AB = 5, PQ = 6 and QR = 10.

∴A(△ABC)/A(△PQR)

=AB×BC/PQ×QR

=5×9/6×10

=3/4

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