1. Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 6. Find the ratio of areas of these triangles.
Answers
Answered by
2
b×h÷b×h=9×5÷1×6
=45÷60
=3:5
Answered by
13
Answer:
Let ABC and PQR be two right triangles with AB ⊥ BC and PQ ⊥ QR.
Given:
BC = 9, AB = 5, PQ = 6 and QR = 10.
∴A(△ABC)/A(△PQR)
=AB×BC/PQ×QR
=5×9/6×10
=3/4
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