Question

1. Base of a triangle is 9 and height is 5. Base of another triangle is 10 and height
is 6. Find the ratio of areas of these triangles.​

Answer 1

Area(△ABC)÷Area of △PQR

(1/2×AC×BC)÷(1/2×PM×QR)

(1/2×5×9)÷(1/2×6×10)

=(3/4)

Hence, Ratio of Area of △ABC:Area of △PQR=3:4

Answer 2

Heya !!

Here's your answer.. ⬇⬇

♦ Given :- Let The triangle be ∆ABC and ∆PQR.

In ∆ABC,

Base of ∆ABC is BC = 9cm

Altitude of ∆ABC is AE = 5cm

In ∆PQR,

Base is QR = 10cm

Altitude is PM = 6cm

♦ To Find :- Ratio of Area of ∆ABC and ∆PQR

♦ Solution :-

$= \frac{area \: \: of \: \: abc}{area \: \: of \: \: pqr} \\ \\ = \frac{ \frac{1}{2} \times ae \times bc }{ \frac{1}{2} \times pm \times qr } \\ \\ = \frac{ \frac{1}{2} \times 5 \times 9 }{ \frac{1}{2} \times 6 \times 10} \\ \\ = \frac{3}{4}$

Hence, Ratio of Area of ∆ABC to ∆PQR is 3:4

Hope it helps..

Thanks. (: