Question

1. Bashir Corporation produces x microprocessor
chips each month only from April to July and
ships 50% of the chips manufactured every month
at the beginning of each month from August to
March. Bashir Corporation incurs a rental cost of
$0.20 on every chip per month from August to
March that is not shipped. In terms of x, what is
the total rental cost incurred by Bashir
Corporation in a year?
(A) 0.80 x
(B) 1.20x
(C) 2.40 x
(D) 2.80 x
(E) 20 x​

Answer 1

Answer:

Step-by-step explanation:

Let the chips manufactured every month = x = 100

Thus, total chips manufactured from April to July = 4 x 100 = 400

50 chips are shipped every month from August to March

Hence, @ rate of $0.2 per chip-

In Aug - out of 400 chips 50 are shipped. Remaining 350 will incur a rental of 350 x 0.2 = $70    

In Sep - out of 350 chips 50 are shipped. Remaining 300 will incur a rental of 300 x 0.2 = $60    

In Oct - out of 300 chips 50 are shipped. Remaining 250 will incur a rental of 250 x 0.2 = $50  

In Nov - out of 250 chips 50 are shipped. Remaining 200 will incur a rental of 200 x 0.2 = $40

In Dec - out of 200 chips 50 are shipped. Remaining 150 will incur a rental of 150 x 0.2 = $30

In Jan - out of 150 chips 50 are shipped. Remaining 100 will incur a rental of 100 x 0.2 = $20  

In Feb - out of 100 chips 50 are shipped. Remaining 100 will incur a rental of 100 x 0.2 = $10  

In Mar - out of 50 chips 50 are shipped, thus no rent for the month will be incurred.

Therefore, in total an amount of $280 from Aug - Mar has been incurred.

Answer 2

Answer:

Step-by-step explanation:

Arranging the data in ascending order = 5, 8, 10, 15, 15, 24, 28

Total number of observations = N = 7

Mean = Sum of all observations/Number of observations

= (5 + 8 + 10 + 15+ 15 + 24 + 28)/7

= 105/7 = 15

Mean = 15

Median = (N + 1)/2

= (7 + 1)/2

= 4

Since, 4th item is 15 so median is 15.

In the given data, 15 is most occurring value. Therefore, mode is 15. ( As mode (Z) is the frequently occcuring value)

Arithmetic mean = 15

Median (M)= 15

Mode (Z) = 15

Adding four numbers so that the mean and median of the data remain the same and the mode increases by 1.

The required four numbers will be 12, 16, 16 and 16

Thus the new observations - 5, 8, 10, 12, 15, 15, 16, 16, 16, 24, 28

Mean = (5 + 8 + 10 + 12 + 15 + 15 + 16 + 16 + 16 + 24 + 28)/11

= 165/11

= 15

Median = (N + 1)/2 th item

= (11+ 1)/2 th item

= 6th item

Since, 6th item is 15, So, median is 15

Mode (Z) in the above data is 16, as 16 is occurring the maximum number of times.

Therefore, Mean = 15, Median = 15 and Mode (Z) = 16