Question

1/bc(b-a)(c-a)+1/ca(c-b)(a-b)+1/ab(a-c)(b-c)​

Answer 1

Answer:

The answer is 0.

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Step-by-step explanation:

$\frac{1}{bc(b - a)(c - a)} + \frac{1}{ca(c - b)( a- b)} + \frac{1}{ab( a-c )(b -c )} \\ = \frac{ - a(b -c ) - b( c-a ) - c(a - b)}{abc(a - b)(b -c )( c- a)} \\ = \frac{ - ab + ca - bc + ab - ca + bc}{abc(a - b)(b -c )( c- a)} \\ = 0$