Question

1 boy is working on first day, two boys are working on second day, 3 boys are working on third day and similarly one boy is added on next day till 20 boys are working on 20th day. Find the time taken by 5 men to do the same work if one man is twice efficient than one boy.
A 22 days
B 16 days
C 28 days
D 21 days​

Answer 1

Answer:

correct answer is 21 days

Step-by-step explanation:

let 1 boy does 1 Unit Work per day.

Hence Total Work = 1+2+3+....+20

20/2 (1+20)= 21 Units