Question

1. bx/a + ay/b = a²+b²

x + y = 2ab

solve this equation by substitution method

Answer 1

bx/a + ay/b = a2 + b2 ......... eq1

x + y = 2ab .... eq 2..

frm eq 1.. b2x + a2y / ab = a2 + b2

-> b2x + a2y = a3b + b3a

-> b2x - b3a = a3b - a2y

->b2 ( x - ab ) = a2 ( ab - y )

-> frm eq 2 ... b2 ( x - x/2 + y/2 ) = a2 ( x/2 + y/2 - y )

-> b2 ( x/2 - y/2 ) = a2 ( x/2 - y/2 )

-> b2x - b2y = a2x - a2y

-> x ( b2 - a2 ) = y ( b2 - a2 )

-> x = y ..

put the value of x in eq 2.... 2y = 2ab

Answer 2

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