1 by 1 + sin theta + 1 by 1 minus sin theta is equal to 2 secant squared theta
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Answered by
0
LHS =left hand side, RHS =right hand side
LHS
=
1
1
+
sin
θ
+
1
1
−
sin
θ
=
1
−
sin
θ
+
1
+
sin
θ
(
1
+
sin
θ
)
(
1
−
sin
θ
)
->Common Denominator
=
1
−
sin
θ
+
1
+
sin
θ
(
1
+
sin
θ
)
(
1
−
sin
θ
)
=
2
1
−
sin
2
x
=
2
cos
2
x
=
2
⋅
1
cos
2
x
=
2
sec
2
x
=
R
H S
sshazu5856:
mark me as brainliest please
oh god it came like tht?
i used maths keyboard........wait a min
how i should
omg i cant edit.......uh u will get atlast2/cos^2 theta=rhs....dude i cant edit it...sry
Answered by
1
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thts wat i did actually...well u can refer this...but please mark me as brainliest....i did a lot of hardwork to type it in the max keyboard......pleasee
cross multiplication
did u saw
did u *see
or u saw*
u saw?*
can u do my new problem
sshazu5856
she squared it because it is of the form a^2-b^2=(a-b)(a+b)
thats an identity thats how 1 gets squared
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