Question

1 by 2 ka whole cubeplus 1 by 3 ka whole cube minus 5 by 6 ka whole cube without actually calculating the cubes find the value of ​

Answer 1

Answer:

In this question a^3+b^3+c^3=?

a+b+c=0

so answer will be 3abc

that is 3*1\2*1\3*1\6=1\12

Step-by-step explanation:

Answer 2

Hi ,

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If x + y + z = 0 then

x³ + y³ + z³ = 3xyz

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Here ,

x = 1/2 ,

y = 1/3 ,

z = - 5/6

x + y + z

= 1/2 + 1/3 - 5/6

= ( 3 + 2 )/6 - 5/6

= 5/6 - 5/6

= 0 ,

Therefore ,

x³ + y³ + z³

= ( 1/2 )³ + ( 1/3 )³ + ( -5/6 )³

= 3 × ( 1/2 ) × ( 1/3 ) × ( -5/6 )

= - ( 3 × 5 )/ ( 2 × 3 × 6 )

= -5/12

I hope this helps you.