Question

1 by 27 is equals to 9 ^ 5 x minus 7

Answer 1

1/27=9^(5x-7)
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We can write
1/27 as 1/3³
and
9^(5x-7) as{3²}^5x-7

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→1/3³={3²}^(5x-7)
→3^-3=(3)^10x-14

Since base is same on both side now we can compare their power

→-3=10x-14
→-10x=-14+3
→-10x=-11
→10x=11
→x=11/10

Answer 2

Answer :

$\frac{1}{27} = {9}^{5x - 7} \\ \\ write \: the \: number \: in \: exponential \: form \\ with \: base \: 3 \\ \\ \frac{1}{ {3}^{3} } =( {3}^{2} ) {}^{5x - 7} \\ \\ using \: \frac{1}{ {a}^{n} } = {a}^{ - n} \: transform \: the \: expression \\ and \: simplify \: ( {3}^{2} ) {}^{5x - 7} \\ \\ {3}^{ - 3} = {3}^{10x - 14} \\ \\ as \: the \: bases \: are \: same \: so \: we \: can \: set \: the \: exponents \: equal \\ \\ therefore \\ \\ - 3 = 10x - 14 \\ \\ - 10x = - 14 + 3 \\ \\ - 10x = - 11 \\ \\ x = \frac{11}{10} = 1.1$

HOPE IT WOULD HELP YOU