Math, asked by spadma33, 11 months ago

1 by a minus b whole square minus 1 by a square minus b square

Answers

Answered by maruf9210ahmed
0

Answer:0

Step-by-step explanation:

1/(a-b)^2-1/(a^2-b^2)

=1/(a-b)(a-b)-1/(a+b)(a-b)

=(a+b-a-b)/(a-b)^2(a+b)

=0/(a-b)^2(a+b)

=0

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