1 by log 36 base 2+ 1 by log 36 base 3
Answers
Answered by
0
Your answer----
Log2/log36 + log3/log36
= log6 base 36
= 1/2 is answer.
Explanation:
To write this expression in terms of
log2
and
log3
you first have to write number36
as a product of powers of 2
and
3.
36=
6.2
(2⋅3)2
So you can write:
log
36
=log
(2⋅3)2
Now you can use the properties of logarythms which say rhat:
log
ab=
b⋅loga
log
(a⋅b)
=loga+logb
After using rule
1
you get:
log
(2⋅3)2=2
⋅
log
(2⋅3)
Now if you use rule 2
you get the final result:2
⋅
log
(2⋅3)
=2
⋅
(log2+log3)
Now you can write the final answer:
log
36
=2
⋅
(log2+log3)
Answered by
0
Answer:
log2/log36 + log3/log36 = log6 base 36 = 1/2
Step-by-step explanation:
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