Question

1 by log 36 base 2+ 1 by log 36 base 3

Answer 1

Answer:

1 by log 36 base 2+ 1 by log 36 base 3 = (1/2) log 2 base 3.

Step-by-step explanation:

   (1 / log 36 base 2) + (1 / log 36 base 3)

=  (1 / 2 log 6 base 2) + (1 / 2 log 6 base 3)

=  (1/2) log 2 base 3.

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Answer 2

Answer:

answer is 1/2

Step-by-step explanation:

Given :- $\frac{1}{log_236}+ \frac{1}{log_336}$

Solution :-

Given , $\frac{1}{log_236}+ \frac{1}{log_336}$

By using base change rule ,

$\frac{log_12}{log_136} + \frac{log_12}{log_136} \\\frac{log_12}{log_1(6)^2} + \frac{log_13}{log_1(6)^2} \\\frac{1}{2}*(\frac{log_12}{log_16}+ \frac{log_13}{log_16}) \\\frac{1}{2} *( \frac{log_16}{log_16} )\\\frac{1}{2}$

therefore , answer is 1/2

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