Math, asked by Pampasaha, 11 months ago

1 by logn convergent or not

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Answered by believerbeasttanmay

1

Hey... mate

ans...

Since ln n ≤ n for n ≥ 2, we have 1/ ln n ≥ 1/n, so the series diverges by comparison with the harmonic series, ∑ 1/n.

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