Question

1 by sec theta + tan theta is equal to 1 minus sin theta divided by cos theta is equal to sec theta minus tan theta​

Answer 1

this is the process of solving the question

Answer 2

Answer:

L.H.S =tanθ−secθ+1tanθ+secθ−1

We can write, sec2θ−tan2θ=1

=tanθ−secθ+1tanθ+secθ−(sec2θ−tan2θ)

=tanθ−secθ+1tanθ+secθ−(secθ−tanθ)(secθ+tanθ)

=tanθ−secθ+1(tanθ+secθ){1−(secθ−tanθ)}

=tanθ−secθ+1(tanθ+secθ){1−secθ+tanθ}

=tanθ+secθ

=cosθsinθ+cosθ1

=cosθ1+sinθ

= R.H.S

since L.H.S = R.H.S

tanθ−secθ+1tanθ+secθ−1=cosθ

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